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kafka集群介绍+部署Filebeat+Kafka+ELK

吴wuwu 04-02 09:00 阅读 4

文章目录

题意

题目链接

有一袋球,分别有每个颜色若干个,取orders个球。
每个球的,价值是剩余球的数量。求最大值。

思路

扫描线+贪心

代码

class Solution {
public:
    long solve(long a, long b)
    {
        long mod = 1000000007L;   
        if (a & 1)
            return b / 2 * a % mod;
        return a / 2 * b % mod;
    }
    int maxProfit(vector<int>& inventory, int orders) {
        sort(inventory.begin(), inventory.end());
        long sum = 0;
        long mod = 1000000007L;
        int index = inventory.size() - 1;
        while (index - 1 >= 0 && orders > 0)
        {
            long l = inventory[index - 1];
            long r = inventory[index];
            long width = inventory.size() - index;
            long nums = (r - l) * width;

            if (nums <= orders)
            {
                sum += solve(r + l + 1, r - l) * width;
                sum %= mod;
                orders -= nums;
            }
            else
            {
                long x = orders / width;
                long y = orders % width;
                sum += solve(r + r - x + 1, x) * width;
                sum %= mod;
                sum += y * (r - x);
                sum %= mod;
                orders = 0;
            }
            index --;
            cout << sum << endl;
        }
        if (orders > 0)
        {
            long x = orders / inventory.size();
            long y = orders % inventory.size();
            sum += solve(inventory[0] * 2 - x + 1, x) * inventory.size();
            sum %= mod;
            sum += y * (inventory[0] - x);
            sum %= mod;
        }
        return sum;
    }
};
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