0
点赞
收藏
分享

微信扫一扫

Python中函数无法调用另一个函数的解决方法

对于正常我们在编程中,尤其在python中,各函数之间正常来说都是可以相互调用的,如果发现函数无法调用另一个函数的情况,正常来说会有多种方面的原因。下面的问题我们可以一起看看。

Python中函数无法调用另一个函数的解决方法_python

1、问题背景

在 Python 中,有时会遇到函数无法调用另一个函数的问题。这通常是由于函数内部的 return 语句导致的。return 语句的作用是终止函数的执行并返回一个值给调用者。如果 return 语句出现在函数的中间,那么后面的代码将不会被执行,包括对其他函数的调用。

2、解决方案

为了解决这个问题,需要将函数调用移动到 return 语句之前。在下面的例子中,right_room() 函数中将 opening() 函数的调用移动到了 return 语句之前,这样 opening() 函数就可以被正确调用了。

def right_room():
    print("You see a table with two objects: a map and a code translator")
    print("You can take one object")
    print("Which object do you take?")

    next = raw_input("> ")

    if "map" in next and "code" in next:
        dead("You're greed surpassed your wisdom.")
    elif "map" in next:
        print("OK, you have the map.")
        theobject = "map"
        print("Now you must exit and go ahead")
        opening()  # Moved the function call before the return statement
        return theobject
    elif "code" in next:
        print("OK, you have the code.")
        theobject = "code"
        print("Now you must exit and go ahead.")
        opening()  # Moved the function call before the return statement
        return theobject

def opening():
    print("You're in a Labrynthe.")
    print("There's a door on your left.")
    print("There's a door on your right.")
    print("Or you can go ahead.")

    next = raw_input("> ")

    if "right" in next:
        right_room()
    elif "left" in next:
        left_room()
    elif "ahead" in next:
        ahead()
    else: 
        print("Which way will you go?")

除了移动函数调用的位置,还可以通过使用异常处理来解决这个问题。在下面的例子中,right_room() 函数使用了 try 语句来捕获 opening() 函数可能抛出的异常。如果 opening() 函数抛出了异常,那么 right_room() 函数将继续执行后面的代码,而不会被终止。

def right_room():
    print("You see a table with two objects: a map and a code translator")
    print("You can take one object")
    print("Which object do you take?")

    next = raw_input("> ")

    if "map" in next and "code" in next:
        dead("You're greed surpassed your wisdom.")
    elif "map" in next:
        print("OK, you have the map.")
        theobject = "map"
        print("Now you must exit and go ahead")
    elif "code" in next:
        print("OK, you have the code.")
        theobject = "code"
        print("Now you must exit and go ahead.")
    try:
        opening()  # Moved the function call inside the try block
    except Exception as e:
        print("An error occurred: {}".format(e))

def opening():
    print("You're in a Labrynthe.")
    print("There's a door on your left.")
    print("There's a door on your right.")
    print("Or you can go ahead.")

    next = raw_input("> ")

    if "right" in next:
        right_room()
    elif "left" in next:
        left_room()
    elif "ahead" in next:
        ahead()
    else: 
        print("Which way will you go?")

上面就是今天的全部内容了,如果您遇到了函数无法调用另一个函数的具体问题,可以提供更多的细节或代码示例,以便我可以更具体地帮助您解决问题。

举报

相关推荐

0 条评论