1001 I love cube
一道数学题吧,其实比赛的时候没太看懂题,n=3,实在数不出72个等边三角形,n=4有288个,n每加一,多出n^3*8个等边三角形,这道题的规律就是对于n个结点的正立方体,1~n-1个(n-i)*8相加

#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
const int mod = 1e9+7;
ll n;
ll ans;
int main(){
	int t;
	cin>>t;
	while(t--){
		cin>>n;
		n=n-1;
		if(n<=0){
			cout<<"0"<<endl;
			continue;
		}
		ll k=n%mod;
		ll l=(n+1)%mod;
		k=(k*k)%mod;
		l=(l*l)%mod;
		ans=(k*l)%mod;
		ans=(2*ans)%mod;
		cout<<ans<<endl;
	}
	return 0;
}