import math  
  
def lcm(a, b):  
    return a * b // math.gcd(a, b)  
  
def lcm_range(n):  
    lcm_value = 1  
    for i in range(2, n+1):  
        lcm_value = lcm(lcm_value, i)  
    return lcm_value  
  
n = 81  # 输入给定的数值n  
result = lcm_range(n)  
print(f"1到{n}的所有数字的最小公倍数是：{result}")

上述gpt给的答案是错的,验证数字81