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利用切片,一次修改多个数据
 iterable: 容器,range对象,迭代器
lst[1:4] = ("张果老","吕洞宾","铁拐李","何仙姑")
lst[1:4] =  1234                         # error 必须为Iterable类型才可以赋值
lst[1:4] = "1234"
print(lst)
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利用切片,切几个元素就修改几个元素
 lst = ["张治中","曹国晋","宋浩","欧阳郁郁","范李评","李文豪","申艳英","刘霞"]	
print(lst[::3] )                        #0 3 6 9 12 .... 张治中 欧阳郁郁 申艳英
lst[::3] = ["王源","王俊凯","易烊千玺"]
lst[::3] = ["王源","王俊凯"]              # error
print(lst)
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列表的删除 ( 可切片 )
 lst = ["张治中","曹国晋","宋浩","欧阳郁郁","范李评","李文豪","申艳英","刘霞"]	
删除一个元素
  del lst[0]
  print(lst)
  
删除多个元素
 del lst[0:3]                         # 0 1 2 
 print(lst)
 注意点1
res = lst[0:3]                       # 删除是指向0:3这些元素的变量res本身,不是列表
del res
print(lst)
注意点2
tup = (1,2,3,[4,5])                  # 改变的是列表,不是元组
tup[-1][-1] = 6
print(tup)
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去掉列表所有重复元素
 常规写法一
lst = ["a","b","a",3]
res = set(lst)
print( list(res) )                     # ["a","b","3"]
 按照次序来算
append 从后面插入,追加
lst = []
lst.append(1)
lst.append(2)
lst.append(3)
print(lst)                             # [1,2,3]
 进阶写法二  [保证次序]
lst = ["a","b","a",3]
lst_new = []
for i in lst:                         # 不会你就for i in 先把数据跑起来
	if i not in lst_new:              # 如果不在新列表里,就插入
		lst_new.append(i)             # 插入
print(lst_new)