冒泡排序O(n^2)
def buble(n):
for i in range(n-1):
for j in range(n-1):
if lis[j] > lis[j+1]:
lis[j],lis[j+1] = lis[j+1],lis[j]
lis = [3,2,1]
buble(3)
print(lis)
冒泡排序(easy)
阅读 112
2022-07-04
冒泡排序O(n^2)
def buble(n):
for i in range(n-1):
for j in range(n-1):
if lis[j] > lis[j+1]:
lis[j],lis[j+1] = lis[j+1],lis[j]
lis = [3,2,1]
buble(3)
print(lis)
相关推荐
精彩评论(0)