MySQL 经典练习 50 题（答案易理解）

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2022-04-13

文章目录

创建数据库和表

数据库

drop database if exists mysql_test cascade;
create database mysql_test;
use mysql_test;

学生表

创建学生表

create table student (
	s_id int,
	s_name varchar(8),
	s_birth date,
	s_sex varchar(4)
);

插入学生数据

insert into student values
(1,'赵雷','1990-01-01','男'),
(2,'钱电','1990-12-21','男'),
(3,'孙风','1990-05-20','男'),
(4,'李云','1990-08-06','男'),
(5,'周梅','1991-12-01','女'),
(6,'吴兰','1992-03-01','女'),
(7,'郑竹','1989-07-01','女'),
(8,'王菊','1990-01-20','女');

课程表 course

创建课程表 course

create table teacher (
	t_id int,
	t_name varchar(8)
);

插入课程数据

insert into teacher values
(1,'张三'),
(2,'李四'),
(3,'王五');

教师表 teacher

创建教师表 teacher

create table teacher (
	t_id int,
	t_name varchar(8)
);

插入教师数据

insert into teacher values
(1,'张三'),
(2,'李四'),
(3,'王五');

成绩表 score

创建成绩表 score

create table score (
	s_id int,
	c_id int,
	s_score int
);

插入成绩数据

insert into score values
(1,1,80),
(1,2,90),
(1,3,99),
(2,1,70),
(2,2,60),
(2,3,65),
(3,1,80),
(3,2,80),
(3,3,80),
(4,1,50),
(4,2,30),
(4,3,40),
(5,1,76),
(5,2,87),
(6,1,31),
(6,3,34),
(7,2,89),
(7,3,98);

表关系
引用了这位老兄的图，结合几个参考答案汇总出个人认为易理解的答案并运行通过。
引用：https://blog.csdn.net/GodSuzzZ/article/details/106930311

经典练习 50 题

1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

select s.*,sc1.s_score as score_01,sc2.s_score as score_02
from student s
inner join (
	select * from score where c_id = 1
) sc1
on s.s_id = sc1.s_id
inner join (
	select * from score where c_id = 2
) sc2
on s.s_id = sc2.s_id
where sc1.s_score > sc2.s_score;

+------+--------+------------+-------+----------+----------+
| s_id | s_name | s_birth    | s_sex | score_01 | score_02 |
+------+--------+------------+-------+----------+----------+
|    2 | 钱电   | 1990-12-21 | 男    |       70 |       60 |
|    4 | 李云   | 1990-08-06 | 男    |       50 |       30 |
+------+--------+------------+-------+----------+----------+

2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

select s.*,sc1.s_score as score_01,sc2.s_score as score_02
from student s
inner join (
	select * from score where c_id = 1
) sc1
on s.s_id = sc1.s_id
inner join (
	select * from score where c_id = 2
) sc2
on s.s_id = sc2.s_id
where sc1.s_score < sc2.s_score;

+------+--------+------------+-------+----------+----------+
| s_id | s_name | s_birth    | s_sex | score_01 | score_02 |
+------+--------+------------+-------+----------+----------+
|    1 | 赵雷   | 1990-01-01 | 男    |       80 |       90 |
|    5 | 周梅   | 1991-12-01 | 女    |       76 |       87 |
+------+--------+------------+-------+----------+----------+

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

select s.s_id,s.s_name,round(avg_score, 2) as avg_score
from student s
inner join (
	select s_id,avg(s_score) as avg_score
	from score
	group by s_id
	having avg_score >= 60
) t1
on s.s_id = t1.s_id;

+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
|    1 | 赵雷   | 89.67     |
|    2 | 钱电   | 65.00     |
|    3 | 孙风   | 80.00     |
|    5 | 周梅   | 81.50     |
|    7 | 郑竹   | 93.50     |
+------+--------+-----------+

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)

select s.s_id,s.s_name,ifnull(round(avg_score, 2), 0) as avg_score
from student s
left join (
	select s_id,avg(s_score) as avg_score
	from score
	group by s_id
) t1
on s.s_id = t1.s_id
where avg_score is null or avg_score < 60;

+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
|    4 | 李云   | 40.00     |
|    6 | 吴兰   | 32.50     |
|    8 | 王菊   | 0.00      |
+------+--------+-----------+

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

select s.s_id,s.s_name,ifnull(cnt_course, 0) as cnt_course,ifnull(sum_score, 0) as sum_score
from student s
left join (
	select s_id,count(*) as cnt_course,sum(s_score) as sum_score
	from score
	group by s_id
) t1
on s.s_id = t1.s_id;

+------+--------+------------+-----------+
| s_id | s_name | cnt_course | sum_score |
+------+--------+------------+-----------+
|    1 | 赵雷   |          3 | 269       |
|    2 | 钱电   |          3 | 195       |
|    3 | 孙风   |          3 | 240       |
|    4 | 李云   |          3 | 120       |
|    5 | 周梅   |          2 | 163       |
|    6 | 吴兰   |          2 | 65        |
|    7 | 郑竹   |          2 | 187       |
|    8 | 王菊   |          0 | 0         |
+------+--------+------------+-----------+

6、查询"李"姓老师的数量

select count(*) as cnt_name_li
from teacher
where t_name like '李%';

+-------------+
| cnt_name_li |
+-------------+
|           1 |
+-------------+

7、询学过"张三"老师授课的同学的信息

SELECT s.*,t.t_id,t_name FROM Teacher t
LEFT JOIN Course c ON t.t_id=c.t_id -- 教 师 表 和 课 程 表
LEFT JOIN Score sc ON c.c_id=sc.c_id -- 课 程 表 和 成 绩 表
LEFT JOIN Student s ON s.s_id=sc.s_id -- 成 绩 表 和 学 生 信 息 表
WHERE t.t_name=' 张 三 ';

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    1 | 赵雷   | 1990-01-01 | 男    |
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
|    5 | 周梅   | 1991-12-01 | 女    |
|    7 | 郑竹   | 1989-07-01 | 女    |
+------+--------+------------+-------+

8、查询没学过"张三"老师授课的同学的信息

SELECT s1.*
FROM Student s1
JOIN Score s2
ON s1.s_id=s2.s_id
WHERE s2.c_id NOT IN (
SELECT c_id FROM Course c WHERE t_id=( -- 1. 通 过 老 师 找 出 其 对 应 的 课 程
SELECT t_id FROM Teacher t WHERE t_name=' 张 三 '
)
);

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    6 | 吴兰   | 1992-03-01 | 女    |
|    8 | 王菊   | 1990-01-20 | 女    |
+------+--------+------------+-------+

9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

SELECT s1.*
FROM Student s1
WHERE s_id IN (
SELECT s2.s_id FROM Score s2
JOIN Score s3
ON s2.s_id=s3.s_id
WHERE s2.c_id='01' AND s3.c_id='02'
);

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    1 | 赵雷   | 1990-01-01 | 男    |
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
|    5 | 周梅   | 1991-12-01 | 女    |
+------+--------+------------+-------+

10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

SELECT s1.*
FROM Student s1
WHERE s1.s_id IN (SELECT s_id FROM Score WHERE c_id='01') -- 修 过 01 课 程 ， 要 保留
AND s1.s_id NOT IN (SELECT s_id FROM Score WHERE c_id='02'); -- 哪 些 人 修 过 02 需 要 排 除

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    6 | 吴兰   | 1992-03-01 | 女    |
+------+--------+------------+-------+

11、查询没有学全所有课程的同学的信息

select *
from student
where s_id not in (
	select s_id
	from score
	group by s_id
	having count(*) = (
		select count(*) from course
	)
);

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    5 | 周梅   | 1991-12-01 | 女    |
|    6 | 吴兰   | 1992-03-01 | 女    |
|    7 | 郑竹   | 1989-07-01 | 女    |
|    8 | 王菊   | 1990-01-20 | 女    |
+------+--------+------------+-------+

12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息

select *
from student
where s_id in (
	select distinct s_id
	from score s
	inner join (
		select c_id from score where s_id = 1
	) t1
	on s.c_id = t1.c_id
);


+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    1 | 赵雷   | 1990-01-01 | 男    |
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
|    5 | 周梅   | 1991-12-01 | 女    |
|    6 | 吴兰   | 1992-03-01 | 女    |
|    7 | 郑竹   | 1989-07-01 | 女    |
+------+--------+------------+-------+

13、查询和"01"号的同学学习的课程完全相同的其他同学的信息

select *
from student
where s_id in (
	 select s_id
	 from score s
	 inner join (
		select c_id from score where s_id = 1
	 ) t1
	 on s.c_id = t1.c_id
	 where s_id != 1
	 group by s_id having count(*) = (
		select count(*) from score where s_id = 1
	 )
);

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
+------+--------+------------+-------+

14、查询没学过"张三"老师讲授的任一门课程的学生姓名

select s_name
from student
where s_id not in (
	select s_id
	from score sc
	inner join (
		select c_id
		from course c
		inner join teacher t on c.t_id = t.t_id
		where t_name = '张三'
	) t1
	on sc.c_id = t1.c_id
);

+--------+
| s_name |
+--------+
| 吴兰   |
| 王菊   |
+--------+

15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩

select s.s_id,s.s_name,round(avg(s_score), 2) as avg_score
from student s
inner join (
	select s_id
	from score
	where s_score < 60
	group by s_id
	having count(*) >= 2
) t1
on s.s_id = t1.s_id
inner join score sc on s.s_id = sc.s_id
group by s.s_id;

+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
|    4 | 李云   | 40.00     |
|    6 | 吴兰   | 32.50     |
+------+--------+-----------+

16、检索"01"课程分数小于60，按分数降序排列的学生信息

select s.*,s_score as score_01
from student s
inner join (
	select s_id,s_score
	from score
	where c_id = 1
	and s_score < 60
) t1
on s.s_id = t1.s_id
order by score_01 desc;

+------+--------+------------+-------+----------+
| s_id | s_name | s_birth    | s_sex | score_01 |
+------+--------+------------+-------+----------+
|    4 | 李云   | 1990-08-06 | 男    |       50 |
|    6 | 吴兰   | 1992-03-01 | 女    |       31 |
+------+--------+------------+-------+----------+

17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

select
	s.s_id as 学号,s.s_name as 姓名,
	sum(case c_id when 1 then s_score else 0 end) as 语文,
	sum(case c_id when 2 then s_score else 0 end) as 数学,
	sum(case c_id when 3 then s_score else 0 end) as 英语,
	ifnull(round(avg(s_score), 2), 0) as 平均成绩
from student s
left join score sc on s.s_id = sc.s_id
group by s.s_id
order by 平均成绩 desc;

+------+------+------+------+------+----------+
| 学号 | 姓名 | 语文 | 数学 | 英语 | 平均成绩 |
+------+------+------+------+------+----------+
|    7 | 郑竹 | 0    | 89   | 98   | 93.50    |
|    1 | 赵雷 | 80   | 90   | 99   | 89.67    |
|    5 | 周梅 | 76   | 87   | 0    | 81.50    |
|    3 | 孙风 | 80   | 80   | 80   | 80.00    |
|    2 | 钱电 | 70   | 60   | 65   | 65.00    |
|    4 | 李云 | 50   | 30   | 40   | 40.00    |
|    6 | 吴兰 | 31   | 0    | 34   | 32.50    |
|    8 | 王菊 | 0    | 0    | 0    | 0.00     |
+------+------+------+------+------+----------+

18、查询各科成绩最高分、最低分和平均分，以如下形式显示：

课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率
– 及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90

select
    c.c_id as 课程ID,c.c_name as 课程name,
	max(s_score) as 最高分,
	min(s_score) as 最低分,
	round(avg(s_score), 2) as 平均分,
	concat(round(sum(case when s_score >= 60 then 1 else 0 end) / count(*) * 100, 2), '%') as 及格率,
	concat(round(sum(case when s_score between 70 and 80 then 1 else 0 end) / count(*) * 100, 2), '%') as 中等率,
	concat(round(sum(case when s_score between 80 and 90 then 1 else 0 end) / count(*) * 100, 2), '%') as 优良率,
	concat(round(sum(case when s_score >= 90 then 1 else 0 end) / count(*) * 100, 2), '%') as 优秀率
from course c
inner join score s on c.c_id = s.c_id
group by c.c_id;

+--------+----------+--------+--------+--------+--------+--------+--------+--------+
| 课程ID | 课程name | 最高分 | 最低分 | 平均分 | 及格率 | 中等率 | 优良率 | 优秀率 |
+--------+----------+--------+--------+--------+--------+--------+--------+--------+
|      1 | 语文     |     80 |     31 | 64.50  | 66.67% | 66.67% | 33.33% | 0.00%  |
|      2 | 数学     |     90 |     30 | 72.67  | 83.33% | 16.67% | 66.67% | 16.67% |
|      3 | 英语     |     99 |     34 | 69.33  | 66.67% | 16.67% | 16.67% | 33.33% |
+--------+----------+--------+--------+--------+--------+--------+--------+--------+

19、按各科成绩进行排序，并显示排名

暂时没找到简单易懂解法

20、查询学生的总成绩并进行排名

SELECT
s.s_id
,s.s_name
,SUM(sc.s_score) score
FROM Student s
JOIN Score sc
ON s.s_id = sc.s_id
GROUP BY s.s_id
ORDER BY 3 DESC;

备注：没搞出来rank

+------+------+--------+-----------+
| rank | s_id | s_name | sum_score |
+------+------+--------+-----------+
|    1 |    1 | 赵雷   | 269       |
|    2 |    3 | 孙风   | 240       |
|    3 |    2 | 钱电   | 195       |
|    4 |    7 | 郑竹   | 187       |
|    5 |    5 | 周梅   | 163       |
|    6 |    4 | 李云   | 120       |
|    7 |    6 | 吴兰   | 65        |
+------+------+--------+-----------+

21、查询不同老师所教不同课程平均分从高到低显示

select t.t_id,t.t_name,c.c_id,c.c_name,round(avg(s_score), 2) as avg_score
from score sc
inner join course c on sc.c_id = c.c_id
inner join teacher t on t.t_id = c.t_id
group by t.t_id,c.c_id
order by t.t_id,avg_score desc;


+------+--------+------+--------+-----------+
| t_id | t_name | c_id | c_name | avg_score |
+------+--------+------+--------+-----------+
|    1 | 张三   |    2 | 数学   | 72.67     |
|    2 | 李四   |    1 | 语文   | 64.50     |
|    3 | 王五   |    3 | 英语   | 69.33     |
+------+--------+------+--------+-----------+

22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

暂时没找到简单易懂解法

23、统计各科成绩各分数段人数：课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比

select
	c.c_id as 课程编号,c.c_name as 课程名称,
	sum(case when s_score between 85 and 100 then 1 else 0 end) as '[100-85]',
	concat(round(sum(case when s_score between 85 and 100 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
	sum(case when s_score between 70 and 85 then 1 else 0 end) as '[85-70]',
	concat(round(sum(case when s_score between 70 and 85 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
	sum(case when s_score between 60 and 70 then 1 else 0 end) as '[70-60]',
	concat(round(sum(case when s_score between 60 and 70 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
	sum(case when s_score between 0 and 60 then 1 else 0 end) as '[0-60]',
	concat(round(sum(case when s_score between 0 and 60 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比
from course c
inner join score sc
on c.c_id = sc.c_id
group by c.c_id;

+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+
| 课程编号 | 课程名称 | [100-85] | 百分比 | [85-70] | 百分比 | [70-60] | 百分比 | [0-60] | 百分比 |
+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+
|        1 | 语文     | 0        | 0.00%  | 4       | 66.67% | 1       | 16.67% | 2      | 33.33% |
|        2 | 数学     | 3        | 50.00% | 1       | 16.67% | 1       | 16.67% | 2      | 33.33% |
|        3 | 英语     | 2        | 33.33% | 1       | 16.67% | 1       | 16.67% | 2      | 33.33% |
+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+

24、查询学生平均成绩及其名次

select
sc.s_id
,s.s_name
,round(avg(sc.s_score),2) avg_score
from Score sc
join Student s
on sc.s_id=s.s_id
group by sc.s_id,s.s_name;

+------+------+--------+-----------+
| rank | s_id | s_name | avg_score |
+------+------+--------+-----------+
|    1 |    7 | 郑竹   | 93.50     |
|    2 |    1 | 赵雷   | 89.67     |
|    3 |    5 | 周梅   | 81.50     |
|    4 |    3 | 孙风   | 80.00     |
|    5 |    2 | 钱电   | 65.00     |
|    6 |    4 | 李云   | 40.00     |
|    7 |    6 | 吴兰   | 32.50     |
+------+------+--------+-----------+

25、查询各科成绩前三名的记录

26、查询每门课程被选修的学生数

select c.c_id,c.c_name,cnt_student
from course c
inner join (
	select c_id,count(*) as cnt_student
	from score
	group by c_id
) t1
on c.c_id = t1.c_id;

+------+--------+-------------+
| c_id | c_name | cnt_student |
+------+--------+-------------+
|    1 | 语文   |           6 |
|    2 | 数学   |           6 |
|    3 | 英语   |           6 |
+------+--------+-------------+

27、查询出只有两门课程的全部学生的学号和姓名

select s_id,s_name
from student
where s_id in (
	select s_id
	from score
	group by s_id
	having count(*) = 2
);

+------+--------+
| s_id | s_name |
+------+--------+
|    5 | 周梅   |
|    6 | 吴兰   |
|    7 | 郑竹   |
+------+--------+

28、查询男生、女生人数

select s_sex,count(*) as cnt_sex
from student
group by s_sex;

+-------+---------+
| s_sex | cnt_sex |
+-------+---------+
| 女    |       4 |
| 男    |       4 |
+-------+---------+

29、查询名字中含有"风"字的学生信息

select *
from student
where s_name like '%风%';

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    3 | 孙风   | 1990-05-20 | 男    |
+------+--------+------------+-------+

30、查询同名同性学生名单，并统计同名人数

select *,count(*) as cnt_student
from student
group by s_name,s_sex
having cnt_student > 1;

+-----------+
| Empty set |
+-----------+

31、查询1990年出生的学生名单

select *
from student
where year(s_birth) = '1990';

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    1 | 赵雷   | 1990-01-01 | 男    |
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
|    8 | 王菊   | 1990-01-20 | 女    |
+------+--------+------------+-------+

32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列

select c.c_id,c.c_name,avg_score
from course c
inner join (
	select c_id,round(avg(s_score), 2) as avg_score
	from score
	group by c_id
) t1
on c.c_id = t1.c_id
order by avg_score desc,c.c_id;

+------+--------+-----------+
| c_id | c_name | avg_score |
+------+--------+-----------+
|    2 | 数学   | 72.67     |
|    3 | 英语   | 69.33     |
|    1 | 语文   | 64.50     |
+------+--------+-----------+

33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

select s.s_id,s.s_name,avg_score
from student s
inner join (
	select s_id,round(avg(s_score), 2) as avg_score
	from score
	group by s_id
	having avg_score >= 85
) t1
on s.s_id = t1.s_id;

+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
|    1 | 赵雷   | 89.67     |
|    7 | 郑竹   | 93.50     |
+------+--------+-----------+

SELECT s_name,s_score FROM student 
JOIN score ON student.s_id = score.s_id 
WHERE score.c_id IN 
(SELECT c_id FROM course WHERE c_name = ' 数 学 ')
AND s_score < 60 ;

34、查询课程名称为"数学"，且分数低于60的学生姓名和分数

自己的方法更容易理解些

SELECT s_name,s_score FROM student 
JOIN score ON student.s_id = score.s_id 
WHERE score.c_id IN 
(SELECT c_id FROM course WHERE c_name = ' 数 学 ')
AND s_score < 60 ;

+--------+---------+
| s_name | s_score |
+--------+---------+
| 李云   |      30 |
+--------+---------+

35、查询所有学生的课程及分数情况

select
	s.s_id,s.s_name,
	sum(case c_id when 1 then s_score else 0 end) as 语文,
	sum(case c_id when 2 then s_score else 0 end) as 数学,
	sum(case c_id when 3 then s_score else 0 end) as 英语
from student s
left join score sc on s.s_id = sc.s_id
group by s.s_id;

+------+--------+------+------+------+
| s_id | s_name | 语文 | 数学 | 英语 |
+------+--------+------+------+------+
|    1 | 赵雷   | 80   | 90   | 99   |
|    2 | 钱电   | 70   | 60   | 65   |
|    3 | 孙风   | 80   | 80   | 80   |
|    4 | 李云   | 50   | 30   | 40   |
|    5 | 周梅   | 76   | 87   | 0    |
|    6 | 吴兰   | 31   | 0    | 34   |
|    7 | 郑竹   | 0    | 89   | 98   |
|    8 | 王菊   | 0    | 0    | 0    |
+------+--------+------+------+------+

36、查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数

select s_name,c_name,s_score
from score sc
inner join student s on sc.s_id =  s.s_id
inner join course c on sc.c_id = c.c_id
where s_score > 70
group by s.s_id;

+--------+--------+---------+
| s_name | c_name | s_score |
+--------+--------+---------+
| 赵雷   | 语文   |      80 |
| 孙风   | 语文   |      80 |
| 周梅   | 语文   |      76 |
| 郑竹   | 数学   |      89 |
+--------+--------+---------+

37、查询课程不及格的学生

select s.s_id,s.s_name,c.c_id,c.c_name,s_score
from score sc
inner join student s on sc.s_id =  s.s_id
inner join course c on sc.c_id = c.c_id
where s_score < 60;


+------+--------+------+--------+---------+
| s_id | s_name | c_id | c_name | s_score |
+------+--------+------+--------+---------+
|    4 | 李云   |    1 | 语文   |      50 |
|    4 | 李云   |    2 | 数学   |      30 |
|    4 | 李云   |    3 | 英语   |      40 |
|    6 | 吴兰   |    1 | 语文   |      31 |
|    6 | 吴兰   |    3 | 英语   |      34 |
+------+--------+------+--------+---------+

38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

select s.s_id,s.s_name
from student s
where s_id in (
	select s_id
	from score
	where c_id = 1
	and s_score >= 80
);

+------+--------+
| s_id | s_name |
+------+--------+
|    1 | 赵雷   |
|    3 | 孙风   |
+------+--------+

39、求每门课程的学生人数

select c.c_id,c.c_name,cnt_student
from course c
inner join (
	select c_id,count(*) as cnt_student
	from score
	group by c_id
) t1
on c.c_id = t1.c_id;

+------+--------+-------------+
| c_id | c_name | cnt_student |
+------+--------+-------------+
|    1 | 语文   |           6 |
|    2 | 数学   |           6 |
|    3 | 英语   |           6 |
+------+--------+-------------+

40、查询选修"张三"老师所授课程的学生中，成绩最高的学生信息及其成绩

select s.*,s_score as max_score
from student s
inner join (
	select s_id,s_score
	from score sc
	inner join (
		select c_id
		from course c
		inner join teacher t on c.t_id = t.t_id
		where t_name = '张三'
	) t1
	on sc.c_id = t1.c_id
	order by s_score desc
	limit 1
) t2
on s.s_id = t2.s_id;

+------+--------+------------+-------+-----------+
| s_id | s_name | s_birth    | s_sex | max_score |
+------+--------+------------+-------+-----------+
|    1 | 赵雷   | 1990-01-01 | 男    |        90 |
+------+--------+------------+-------+-----------+

41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

SELECT a.c_id, a.s_id, a.s_score
FROM score a
 INNER JOIN score b
 ON a.s_id = b.s_id
  AND a.c_id != b.c_id
  AND a.s_score = b.s_score
GROUP BY c_id, s_id;

+------+------+---------+
| s_id | c_id | s_score |
+------+------+---------+
|    1 |    1 |      80 |
|    3 |    1 |      80 |
|    3 |    2 |      80 |
|    3 |    3 |      80 |
+------+------+---------+

42、查询每门课程成绩最好的前三名

虽然连接的表多，但是逻辑相对简单

SELECT c.s_id, c.s_name, a.c_id, d.`c_name`,a.s_score
FROM score a
LEFT JOIN score b
ON a.c_id = b.c_id
AND a.s_score < b.s_score
LEFT JOIN student c 
ON c.s_id = a.s_id
LEFT JOIN course d 
ON d.c_id = a.c_id
GROUP BY a.c_id, a.s_id
HAVING COUNT(*) < 3
ORDER BY a.c_id;

+------+--------+------+--------+---------+
| c_id | c_name | s_id | s_name | s_score |
+------+--------+------+--------+---------+
|    1 | 语文   |    1 | 赵雷   |      80 |
|    1 | 语文   |    3 | 孙风   |      80 |
|    1 | 语文   |    5 | 周梅   |      76 |
|    2 | 数学   |    1 | 赵雷   |      90 |
|    2 | 数学   |    7 | 郑竹   |      89 |
|    2 | 数学   |    5 | 周梅   |      87 |
|    3 | 英语   |    1 | 赵雷   |      99 |
|    3 | 英语   |    7 | 郑竹   |      98 |
|    3 | 英语   |    3 | 孙风   |      80 |
+------+--------+------+--------+---------+

43、统计每门课程的学生选修人数（超过5人的课程才统计）

– 要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列

select c.c_id,cnt_student
from course c
inner join (
	select c_id,count(*) as cnt_student
	from score
	group by c_id
	having cnt_student > 5
) t1
on c.c_id = t1.c_id
order by cnt_student desc,c.c_id;

+------+-------------+
| c_id | cnt_student |
+------+-------------+
|    1 |           6 |
|    2 |           6 |
|    3 |           6 |
+------+-------------+

44、检索至少选修两门课程的学生学号

select s_id
from score
group by s_id
having count(*) >= 2;

+------+
| s_id |
+------+
|    1 |
|    2 |
|    3 |
|    4 |
|    5 |
|    6 |
|    7 |
+------+

45、查询选修了全部课程的学生信息

select *
from student
where s_id in (
	select s_id
	from score
	group by s_id
	having count(*) = (
		select count(*) from course
	)
);

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    1 | 赵雷   | 1990-01-01 | 男    |
|    2 | 钱电   | 1990-12-21 | 男    |
|    3 | 孙风   | 1990-05-20 | 男    |
|    4 | 李云   | 1990-08-06 | 男    |
+------+--------+------------+-------+

46、查询各学生的年龄(周岁)

select *
,case when dayofyear(now()) >= dayofyear(s_birth) then year(now()) - year(
s_birth)
when dayofyear(now()) < dayofyear(s_birth) then year(now()) - year(
s_birth) - 1
else 'other' end as 'age'
from Student;

47、查询本周过生日的学生

select *
from Student
where week(s_birth) = week(now());

48、查询下周过生日的学生

select *
from Student
where week(s_birth) = week(now()) + 1; -- 往 前 推 1 周

49、查询本月过生日的学生

select *
from student
where month(s_birth) = month(current_date());

50、查询12月份过生日的学生

select *
from student
where month(s_birth) = 12;

+------+--------+------------+-------+
| s_id | s_name | s_birth    | s_sex |
+------+--------+------------+-------+
|    2 | 钱电   | 1990-12-21 | 男    |
|    5 | 周梅   | 1991-12-01 | 女    |
+------+--------+------------+-------+

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