mysql经纬度空间范围搜索-CFANZ编程社区

今天学习mysql，发现mysql5.7之后也支持空间地理数据类型，也支持相关的搜索。今天就来记录一下，如何经纬度范围查询。

首先建立一张表，表里面需要有两个字段，经度（x）和纬度（y）。

1、距离计算

已知当前位置经纬度（106.550474,29.563755），计算数据库中的点，与当前位置的距离。

mysql<5.7

SELECT 
   shop_name, 
   ((6371 * ACOS(COS(RADIANS(29.563755) ) * COS( RADIANS(`y`)) 
   * COS( RADIANS(`x`) - RADIANS(106.550474)) + SIN(RADIANS(29.563755)) 
   * SIN( RADIANS(`y`))))) * 1000 AS distance 
FROM shop

或者

SELECT
    shop_name,
    ROUND(
        6371 * 2 * ASIN(
            SQRT(
                POW(
                    SIN(
                        (
                            29.563755 * PI() / 180 - `y` * PI() / 180
                        ) / 2
                    ),
                    2
                ) + COS(29.563755 * PI() / 180) * COS(`y` * PI() / 180) * POW(
                    SIN(
                        (
                            106.550474 * PI() / 180 - `x` * PI() / 180
                        ) / 2
                    ),
                    2
                )
            )
        ) * 1000
    ) AS distance
FROM `shop`
ORDER BY distance

该计算方法得到的距离是米。

mysql≥5.7

SELECT shop_name,st_distance_sphere(POINT(106.550474,29.563755), POINT(`x`, `y`)) AS distance FROM shop

该计算方法得到的距离是米。

2、范围搜索

mysql<5.7

SELECT 
   shop_name, 
   ((6371 * ACOS(COS(RADIANS(29.563755) ) * COS( RADIANS(`y`)) 
   * COS( RADIANS(`x`) - RADIANS(106.550474)) + SIN(RADIANS(29.563755)) 
   * SIN( RADIANS(`y`))))) * 1000 AS distance 
FROM `shop`
HAVING distance < 100
ORDER BY distance;

或者

SELECT
    shop_name,
    ROUND(
        6371 * 2 * ASIN(
            SQRT(
                POW(
                    SIN(
                        (
                            29.563755 * PI() / 180 - `y` * PI() / 180
                        ) / 2
                    ),
                    2
                ) + COS(29.563755 * PI() / 180) * COS(`y` * PI() / 180) * POW(
                    SIN(
                        (
                            106.550474 * PI() / 180 - `x` * PI() / 180
                        ) / 2
                    ),
                    2
                )
            )
        ) * 1000
    ) AS distance
FROM `shop`
HAVING distance < 100
ORDER BY distance

mysql≥5.7

SELECT shop_name,st_distance_sphere(POINT(106.550474,29.563755), POINT(`x`, `y`)) AS distance FROM `shop` 
HAVING distance < 100
ORDER BY distance;