#include<iostream>
using namespace std;
int main()
{
int n; //n>0
cin>>n;
if( n & (n-1) )
cout<<"no\n";
else
cout<<"yes\n";
return 0;
}
位运算判断是否是2的幂
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2022-01-03
#include<iostream>
using namespace std;
int main()
{
int n; //n>0
cin>>n;
if( n & (n-1) )
cout<<"no\n";
else
cout<<"yes\n";
return 0;
}
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