continue：对1到100之间的奇数进行求和

#include <stdio.h>

int main()
{
	int i, total;
	for (i = 1, total = 0; i <= 100; i++)
	{
		if (i % 2 == 0)
		{
			continue;//提前结束i为偶数的这轮循环
		}
		total = total + i;
	}
	printf("total=%d\n", total);
}

break

#include <stdio.h>

int main()
{
	int i, total;
	for (i = 1, total = 0; i <= 100; i++)
	{
		if (total > 2000)
		{
			break;//当求和大于2000，就中止循环
		}
		total = total + i;
	}
	printf("total=%d,i=%d\n", total, i);
	return 0;
}