题目:原题链接(简单)
标签:字符串
| 解法 | 时间复杂度 | 空间复杂度 | 执行用时 | 
| Ans 1 (Python) | O(N) | O(N) | 40ms (63.92%) | 
| Ans 2 (Python) | O(N) | O(N) | 36ms (84.78%) | 
| Ans 3 (Python) | 
解法一(替换函数):
def defangIPaddr(self, address: str) -> str:
    return address.replace(".", "[.]")解法二(拆分字符串):
def defangIPaddr(self, address: str) -> str:
    return "[.]".join(address.split("."))









