Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991编译软件：visual studio
编译语言：c语言
参考代码：
#include<cstdio>
int num[10];
int main()
{
int a, b, sum;
scanf_s("%d%d", &a, &b);
sum = a + b;
if (sum < 0)
{
printf("-");
sum = -sum;
}
int len = 0;
if (sum == 0) num[len++] = 0;
while (sum)
{
num[len++] = sum % 10;
sum /= 10;
}
for (int i = len - 1; i >= 0; i--)
{
printf("%d", num[i]);
if (i > 0 &&i % 3 == 0) printf(",");
}
return 0;
}
