SDUT-OJ-逆置正整数

#include <iostream>

using namespace std;


int main()
{

    int a,b, c,n;
    cin>>n;
    a = n / 100;
    b = n / 10 % 10;
    c = n % 10;
        cout<<c * 100 + b * 10 + a;
    return 0;
}