思路:素数筛+二分
Accode:
#include <stdio.h>
#include <iostream>
#include <string.h>
#include <algorithm>
#include <math.h>
#include <map>
using namespace std;
typedef long long ll;
const int maxn = 1e8 + 10;
bool vis[maxn];
int primes[maxn];
int cnt;
void get_primes(int n)
{
vis[0] = vis[1] = 1;
for (int i = 2; i <= n; i ++ )
{
if (!vis[i]) primes[cnt ++ ] = i;
for (int j = 0; primes[j] <= n / i; j ++ )
{
vis[primes[j] * i] = 1;
if (i % primes[j] == 0) break;
}
}
}
int main()
{
ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
get_primes(maxn);
int T;
cin >> T;
while (T -- )
{
int x;
cin >> x;
if (x > 0 && !vis[x])
{
cout << 1 << endl;
continue;
}
if (x > 0 && (!vis[x + x + 1] || !vis[x + x - 1]))
{
cout << 2 << endl;
continue;
}
if (x < 0) x = -x;
for (int i = x + 1; ; i ++ )
{
if (!vis[i])
{
cout << 2 * (i - 1) + 2 << endl;
break;
}
if (!vis[i + i + 1])
{
cout << 2 * (i - 1) + 3 << endl;
break;
}
}
}
return 0;
}