【LeetCode-SQL每日一练】——2. 第二高的薪水-CFANZ编程社区

【LeetCode-SQL每日一练】——2. 第二高的薪水

题目概述

解题思路

方式一

方式二

力扣官方解析

代码实现

方式一

select ifnull((
select max(salary) from Employee 
where 
salary < (select max(salary) from Employee)),null)
as SecondHighestSalary;

输出与预期结果一致，答题成功！

方式二

limit

select
    ifnull(
      (select distinct Salary
       from Employee
       order by Salary desc
        limit 1,1), 
    null) as SecondHighestSalary;

输出与预期结果一致，答题成功！

limit offset

SELECT
    IFNULL(
      (SELECT DISTINCT Salary
       FROM Employee
       ORDER BY Salary DESC
        LIMIT 1 OFFSET 1),
    NULL) AS SecondHighestSalary