详细整理！！html5常用标签

目录

题目

准备数据

分析数据

实现

题目

一家公司想雇佣新员工。公司的工资预算是 70000 美元。公司的招聘标准是：

1. 雇佣最多的高级员工。
2. 在雇佣最多的高级员工后，使用剩余预算雇佣最多的初级员工。

编写一个SQL查询，查找根据上述标准雇佣的高级员工和初级员工的数量。
按 任意顺序 返回结果表。

准备数据

Create table If Not Exists Candidates (employee_id int, experience ENUM('Senior', 'Junior'), salary int)
    Truncate table Candidates
    insert into Candidates (employee_id, experience, salary) values ('1', 'Junior', '10000')
    insert into Candidates (employee_id, experience, salary) values ('9', 'Junior', '10000')
    insert into Candidates (employee_id, experience, salary) values ('2', 'Senior', '20000')
    insert into Candidates (employee_id, experience, salary) values ('11', 'Senior', '20000')
    insert into Candidates (employee_id, experience, salary) values ('13', 'Senior', '50000')
    insert into Candidates (employee_id, experience, salary) values ('4', 'Junior', '40000');

分析数据

实现

with t1 as (
    select employee_id,sum(salary) over(order by salary) total1 from candidates
    where experience = 'Senior'
),t2 as (
    select max(total1) total from t1 where total1 <= 70000
),t3 as (
    select employee_id,sum(salary) over(order by salary) total2 from candidates
    where experience = 'Junior'
)
select 'Senior' as experience,count(distinct  employee_id) accepted_candidates from t1
where total1 <= 70000
union all
select 'Junior' as experience,count(distinct  employee_id) accepted_candidates from t2,t3
where total2 < 70000 - ifnull(total,0)
;