557. 反转字符串中的单词 III

class Solution:
        def reverseWords(self, s):
            """
            :type s: str
            :rtype: str
            """
            words = s.split(' ')
            for i in range(len(words)):
                words[i] = words[i][:: -1]
            return ' '.join(words)

1.主要思路识别空格，以空格分开单词，然后变换为344反转字符串