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CF1101C Division and Union 线段相交问题

343d85639154 2022-05-27 阅读 31

CF1101C Division and Union 线段相交问题_i++

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
//#include
//#pragma GCC optimize(2)
using namespace std;
#define maxn 100005
#define inf 0x7fffffff
//#define INF 1e18
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
#define rdult(x) scanf("%lu",&x)
#define rdlf(x) scanf("%lf",&x)
#define rdstr(x) scanf("%s",x)
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const long long int mod = 1e9 + 7;
#define Mod 1000000000
#define sq(x) (x)*(x)
#define eps 1e-4
typedef pair pii;
#define pi acos(-1.0)
//const int N = 1005;
#define REP(i,n) for(int i=0;i<(n);i++)
typedef pair pii;
inline ll rd() {
ll x = 0;
char c = getchar();
bool f = false;
while (!isdigit(c)) {
if (c == '-') f = true;
c = getchar();
}
while (isdigit(c)) {
x = (x << 1) + (x << 3) + (c ^ 48);
c = getchar();
}
return f ? -x : x;
}

ll gcd(ll a, ll b) {
return b == 0 ? a : gcd(b, a%b);
}
int sqr(int x) { return x * x; }


/*ll ans;
ll exgcd(ll a, ll b, ll &x, ll &y) {
if (!b) {
x = 1; y = 0; return a;
}
ans = exgcd(b, a%b, x, y);
ll t = x; x = y; y = t - a / b * y;
return ans;
}
*/

int T;
int n;
struct node {
int l, r;
bool operator<(const node&rhs)const {
if (l < rhs.l)return true;
if (l > rhs.l)return false;
if (l == rhs.l)return r < rhs.r;
}
}line[maxn];
int l[maxn], r[maxn];

int main() {
//ios::sync_with_stdio(0);
rdint(T);
while (T--) {
rdint(n);
for (int i = 1; i <= n; i++) {
rdint(l[i]); rdint(r[i]);
line[i].l = l[i]; line[i].r = r[i];
}
sort(line + 1, line + 1 + n);
bool fg = false;
int R = -1;
for (int i = 1; i <= n; i++) {
if (i == 1)R = line[i].r;
if (line[i].l > R) {
fg = true; break;
}
else R = max(R, line[i].r);
}
if (!fg) {
cout << -1 << endl;
}
else {
for (int i = 1; i <= n; i++) {
if (r[i] <= R) {
cout << 1 << ' ';
}
else cout << 2 << ' ';
}
cout << endl;
}
}
return 0;
}

 

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