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Codeforces Round #354 (Div. 2) C (二分???)

C. Vasya and String

time limit per test 1 second

memory limit per test 256 megabytes

input standard input

output standard output



High school student Vasya got a string of length n as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotesbeauty of the string as the maximum length of a substring

Vasya can change no more than k

Input


The first line of the input contains two integers n and k (1 ≤ n ≤ 100 000, 0 ≤ k ≤ n) — the length of the string and the maximum number of characters to change.

The second line contains the string, consisting of letters 'a' and 'b' only.

Output

Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than k

Examples

input


4 2
abba


output


4


input


8 1
aabaabaa


output

5


Note

In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".

In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa".


题解:

有一个长度为n的字符串,这个字符串只含有a和b,你可以改变最多k次,问你连续最长的一样的字符串是多长?

从头到尾都遍历-->枚举-->改变 ,贪心最长度。 有点像二分

AC代码:

#include<bits/stdc++.h>
using namespace std;
const int N = 1e5+10;
int n,k;

int f(string s)
{
int l=0,r=-1;
int num=0;
int res=0;
while(++r<s.size())
{
if(s[r]=='b')
num++;
if(num>k)
{
while(s[l++]=='a');
num--;
}
res=max(res,r-l+1);
}

return res;
}

int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
string s;
cin>>n>>k;
cin>>s;
int ans=f(s);
for(int i=0;i<s.size();i++)
s[i]='a'+'b'-s[i];
ans=max(ans,f(s));
cout<<ans<<endl;
return 0;
}



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