各科前两名查询

 //去掉各科第一名后的结果

(select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject));

//去掉各科前两名后的结果

(select * from ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject)))) minus (select * from  ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject)))  where  (subject,score) in (select  subject,max(score) from  ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject))) group by subject))

//用所有的减去 （去掉各科前两名后的结果）  不就是想要的前两名的结果吗？

(select * from stuscore) minus ((select * from ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject)))) minus (select * from  ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject)))  where  (subject,score) in (select  subject,max(score) from  ((select * from stuscore) minus (select * from  stuscore  where  (subject,score) in (select  subject,max(score) from  stuscore group by subject))) group by subject)))

网站上的面试题！

http://zhidao.baidu.com/question/434982390.html?fr=qrl&index=1

有一个学生表(student),里面有 学号(student_id) 功课编号(cid) 学生成绩(corde)三个字段. 用一个SQL查询语句得出:每门功课成绩最好的前2名 @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@

http://zhidao.baidu.com/question/488692022.html?push=related

http://iask.sina.com.cn/b/6039491.html

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