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简单的Restful API例子(Golang)


         RESTful API 这玩意不用多说了,用Go做了个很简单的例子:

               服务端在被调用时返回JSON,

               客户端解析得到相关JSON信息.


服务端源码:

package main

//简单的JSON Restful API演示(服务端)
//author: Xiong Chuan Liang
//date: 2015-2-28

import (
"encoding/json"
"fmt"
"net/http"
"time"
)

type Item struct {
Seq int
Result map[string]int
}

type Message struct {
Dept string
Subject string
Time int64
Detail []Item
}

func getJson() ([]byte, error) {
pass := make(map[string]int)
pass["x"] = 50
pass["c"] = 60
item1 := Item{100, pass}

reject := make(map[string]int)
reject["l"] = 11
reject["d"] = 20
item2 := Item{200, reject}

detail := []Item{item1, item2}
m := Message{"IT", "KPI", time.Now().Unix(), detail}
return json.MarshalIndent(m, "", "")
}

func handler(w http.ResponseWriter, r *http.Request) {
resp, err := getJson()
if err != nil {
panic(err)
}
fmt.Fprintf(w, string(resp))
}

func main() {
http.HandleFunc("/", handler)
http.ListenAndServe("localhost:8085", nil)
}

 服务端源码运行后,可在浏览器中执行看下效果:

  

简单的Restful API例子(Golang)_json

 说明返回是正常的。再用Go写个调用程序测试下:

 

package main

//简单的JSON Restful API演示(调用端)
//author: Xiong Chuan Liang
//date: 2015-2-28

import (
"encoding/json"
"fmt"
"io/ioutil"
"net/http"
"time"
)

type Item struct {
Seq int
Result map[string]int
}

type Message struct {
Dept string
Subject string
Time int64
Detail []Item
}

func main() {
url := "http://localhost:8085"
ret, err := http.Get(url)

if err != nil {
panic(err)
}
defer ret.Body.Close()

body, err := ioutil.ReadAll(ret.Body)
if err != nil {
panic(err)
}

var msg Message
err = json.Unmarshal(body, &msg)
if err != nil {
panic(err)
}

strTime := time.Unix(msg.Time, 0).Format("2006-01-02 15:04:05")
fmt.Println("Dept:", msg.Dept)
fmt.Println("Subject:", msg.Subject)
fmt.Println("Time:", strTime, "\n", msg.Detail)
}

/*
//运行结果:

Dept: IT
Subject: KPI
Time: 2015-02-28 16:43:11
[{100 map[c:60 x:50]} {200 map[d:20 l:11]}]

*/

  从运行结果中可以看到,已正确得到相关JSON信息。 




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