分治思想
leetcode105从前中序遍历序列中构造二叉树
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
HashMap<Integer, Integer> map = new HashMap<>();
;
int N;
int[] pre, in;
public TreeNode buildTree(int[] preorder, int[] inorder) {
if (preorder.length == 0) return null;
pre = preorder;
in = inorder;
N = inorder.length;
for (int i = 0; i < N; i++) {// 空间换时间
map.put(inorder[i], i);
}
return modify(0, N - 1, 0, N - 1);
}
private TreeNode modify(int preStart, int preEnd, int inStart, int inEnd) {
if (preStart > preEnd) return null;
int leftNum = map.get(pre[preStart]) - inStart;
return new TreeNode(pre[preStart],
modify(preStart + 1, preStart + leftNum, inStart, inStart + leftNum - 1),
modify(preStart + leftNum + 1, preEnd, inStart + leftNum + 1, inEnd));
}
}