第二题:
def sort(nums):
for i in range(len(nums) - 1): # 这个循环负责设置冒泡排序进行的次数
for j in range(len(nums) - i - 1): # j为列表下标
if nums[j] > nums[j + 1]:
nums[j], nums[j + 1] = nums[j + 1], nums[j]
return nums
print(sort([4,7,3,8,9]))
第三题:
import itertools
a1 = 'aabbbccaaa'
list1 = [(k, len(list(g))) for k, g in itertools.groupby(a1)]
s = ''
for i in list1:
if i[1] !=1:
s += str(i[1])
s += str(i[0])
print(s)
第四题:
import numpy
import numpy as np
a = np.arange(1,5).reshape(2,2)
print('转置前:\n',a)
print('转置后\n',a.T)
#第五题:
list1= [1,2,3,'a','b','c',1,2,'a','b',3,'c','d','a','b',1]
set1 = set(list1)
result = [(item, list1.count(item)) for item in set1]
result.sort(key=lambda x:x[1], reverse=True)
print(result)