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python元组Tuple的遍历


现提供两种方法对元组进行遍历
 
1)range()
 
#!/usr/bin/python
#-*- coding:UTF-8 -*-
 
 tuple=(("apple",2.0),("grape",3.0),("watermelon",4.0),("grapefruit",5.0))
       for i in range(len(tuple)) :
            for j in range(len(tuple[i])):
                 #print("tuple[",i,"][",j,"]=",end=""),#一种显示方法
                #print("tuple[%d]"%i,"[%d]="%j,end=""),#另一种显示方法
                 print("tuple[%d][%d]"%(i,j))
                 print(tuple[i][j],"")
            print
 
2)map()遍历
 
#!/usr/bin/python
#-*- coding:UTF-8 -*-
#import os
tuple=(("apple",1.0),("grape",2.0),("watermelon",3.0),("grapefruit",4.0))
def ret (x):
    return x    
k=0
for a in map(ret,tuple):
    j=0
    for x in a:
        print("tuple[%d][%d]="%(k,j),end=""),
        print(x," "),
        j+=1
    print
    k+=1

 

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