Lua 10进制转bit 时间戳计算 记录

lua10进制转bit

local function number2bit(n)
    local t = {}
    for i = 7, 0, -1 do
        t[#t + 1] = math.floor(n / 2 ^ i)
        n = n % 2 ^ i
    end
    return t
end
local v = number2bit(255)
for _, value in ipairs(v) do
    print(value)
end
print(tonumber(table.concat(v), 2))

lua断两个时间戳差天数

--判断两个时间戳差天数

local function getDateNum(timeNow, timeNext)
    local ret = 0
    if timeNow and timeNext then
        local now = os.date('*t', timeNow)
        local next = os.date('*t', timeNext)

        if now and next then
            local num1 = os.time({year = now.year, month = now.month, day = now.day})
            local num2 = os.time({year = next.year, month = next.month, day = next.day})
            if num1 and num2 then
                ret = math.abs(num1 - num2) / (3600 * 24)
                ret = math.modf(ret)
            end
        end
    end
    return ret
end

lua判断两个时间戳是否为同一天

local function isToday(timestamp)
    local today = os.date('*t',1647187200)
    local secondOfToday =
        os.time({day = today.day, month = today.month, year = today.year, hour = 0, minute = 0, second = 0})
    if timestamp >= secondOfToday and timestamp < secondOfToday + 24 * 60 * 60 then
        return true
    else
        return false
    end
end