尚硅谷MySQL课后练习题
视频地址：【宋红康】MySQL数据库（mysql安装/基础/高级/优化）_哔哩哔哩_bilibili
数据库资源地址：链接：https://pan.baidu.com/s/1D1mNUa9bTCcED3SothrgpQ 提取码：1328
一、基本的SELECT语句
【题目】
1.查询员工12个月的工资总和，并起别名为ANNUAL SALARY
SELECT employee_id , last_name,salary * 12 "ANNUAL SALARY"
FROM employees;
SELECT employee_id,last_name,salary * 12 * (1 + IFNULL(commission_pct,0)) "ANNUAL SALARY"
FROM employees;
2.查询employees表中去除重复的job_id以后的数据
SELECT DISTINCT job_id
FROM employees;
3.查询工资大于12000的员工姓名和工资
SELECT last_name,salary
FROM employees
WHERE salary > 12000;
4.查询员工号为176的员工的姓名和部门号
SELECT last_name,department_id
FROM employees
WHERE employee_id = 176;
5.显示表 departments 的结构，并查询其中的全部数据
DESC departments;
SELECT * FROM departments;
二、运算符练习
【题目】
1.选择工资不在5000到12000的员工的姓名和工资
SELECT last_name,salary
FROM employees
WHERE salary < 5000 OR salary > 12000;
SELECT last_name,salary
FROM employees
WHERE NOT BETWEEN 5000 AND 12000;
2.选择在20或50号部门工作的员工姓名和部门号
SELECT last_name,department_id
FROM employees
WHERE department_id = 20 OR department_id = 50;
SELECT last_name,department_id
FROM employees
WHERE department_id IN(20, 50);
3.选择公司中没有管理者的员工姓名及job_id
SELECT last_name,job_id
FROM employees
WHERE manager_id <=> NULL;
SELECT last_name,job_id
FROM employees
WHERE manager_id IS NULL;
4.选择公司中有奖金的员工姓名，工资和奖金级别
SELECT last_name,salary,commission_pct
FROM employees
WHERE commission_pct IS NOT NULL;
5.选择员工姓名的第三个字母是a的员工姓名
SELECT last_name
FROM employees
WHERE last_name
LIKE '__a%';
6.选择姓名中有字母a和k的员工姓名
SELECT last_name
FROM employees
WHERE last_name LIKE '%a%k%' OR last_name LIKE '%k%a%';
7.显示出表 employees 表中 first_name 以 'e’结尾的员工信息
SELECT employee_id,first_name,last_name
FROM employees
WHERE first_name LIKE '%e';
8.显示出表 employees 部门编号在 80-100 之间的姓名、工种
SELECT last_name,job_id
FROM employees
WHERE department_id IN(80, 100);
SELECT last_name,job_id
FROM employees
WHERE department_id BETWEEN 80 AND 100;
9.显示出表 employees 的 manager_id 是 100,101,110 的员工姓名、工资、管理者id
SELECT last_name,salary,manager_id
FROM employees
WHERE manager_id = 100
OR manager_id = 101
OR manager_id = 110;
SELECT last_name,salary,manager_id
FROM employees
WHERE manager_id IN (100,101,110);
