指针为什么在使用时,需要强制类型转换。
using namespace std;
class Base {
public:
int a;
Base(int b):a(b){}
void print(){
cout<< "Base a:" << a << endl;
}
};
class Derived :public Base{
public:
int b = 900;
Derived(int a,int b):Base(a){
this->b = b;
}
void print(){
cout<< "Derived a:" << a << " b:"<< b << endl;
}
void hello(){
cout<< "Derived : Hello" << b << endl;
}
};
int main()
{
Base *pb = new Base(30); // pb指向Base类型的内容
Derived *pd = new Derived(40,10); // pd指向Derived类型的内容
pb->print(); // Base a:30
pd->print(); // Derived a:40 b:10
Base *pdd = new Derived(30,90);
pdd->print();// Base a:30,为什么不是Derived a:30 b:90,因为当前指针是指向Base内容的,所以调用的print()是来自基类Base,而不是来自Derived类
((Derived *)pdd)->print();// 进行类型强制转换后,print()才是来自Derived类,所以结果是:Derived a:30 b:90
((Derived *)pb)->print(); // Derived a:30 b:0,pb是指向Base的,现在指向Derived,但Derived的b没有初始化,所以只能是0
((Derived *)pb)->hello();//Derived : Hello0
return 0;
}
输出的结果:
Base a:30
Derived a:40 b:10
Base a:30
Derived a:30 b:90
Derived a:30 b:0
Derived :