LeetCode（数据库）- 当选者

题目链接：​​点击打开链接​​

题目大意：略。

解题思路：略。

AC 代码

-- 解决方案(1)
WITH t1 AS(SELECT v.*, c.Name, ROW_NUMBER() OVER(PARTITION BY v.CandidateId ORDER BY v.CandidateId DESC) `rank` FROM Vote v, Candidate c WHERE v.CandidateId = c.id)

SELECT t1.Name
FROM t1
WHERE t1.rank = (SELECT MAX(`rank`) FROM t1)

-- 解决方案(2)
SELECT Name
FROM Candidate 
WHERE id = (
  SELECT CandidateId id
  FROM Vote
  GROUP BY CandidateId
  ORDER BY count(id) DESC
  LIMIT 1
)