题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT customer_id, COUNT(*) count_no_trans
FROM Visits
WHERE visit_id NOT IN (SELECT DISTINCT visit_id FROM Transactions)
GROUP BY customer_id
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题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT customer_id, COUNT(*) count_no_trans
FROM Visits
WHERE visit_id NOT IN (SELECT DISTINCT visit_id FROM Transactions)
GROUP BY customer_id
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