a letter and a number
3000 ms | 内存限制： 65535
1
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
输出
for each case, you should the result of y+f(x) on a line
样例输入
6 R 1 P 2 G 3 r 1 p 2 g 3
样例输出
19 18 10 -17 -14 -4
# include<stdio.h>
int main()
{
int T,y;
char x;
scanf("%d",&T);
while(T--)
{
getchar();
scanf("%c %d",&x,&y);
if(x>='a' && x<='z')
printf("%d\n",96-x+y);
else if(x>='A' && x<='Z')
printf("%d\n",x-64+y);
}
return 0;
}
