290. Word Pattern

Given a pattern and a string str, find if str follows the same pattern.

Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.

Examples:
pattern = “abba”, str = “dog cat cat dog” should return true.
pattern = “abba”, str = “dog cat cat fish” should return false.
pattern = “aaaa”, str = “dog cat cat dog” should return false.
pattern = “abba”, str = “dog dog dog dog” should return false.
Notes:
You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.

class Solution {
    public boolean wordPattern(String pattern, String str) {
        String[] strs = str.split(" ");  
        if(pattern.length() != strs.length) 
            return false;  
          
        Map<Character, String> map = new HashMap<>();  
        Set<String> unique = new HashSet<>();  
          
        for(int i = 0; i < pattern.length(); i++) {  
            char c = pattern.charAt(i);  
            if(map.containsKey(c)) {  
                if(!map.get(c).equals(strs[i])) 
                    return false;  
            } else {  
                if(unique.contains(strs[i])) 
                    return false;  
                map.put(c, strs[i]);  
                unique.add(strs[i]);  
            }  
        }  
        return true;  
    }
}

/**
 * @param {string} pattern
 * @param {string} str
 * @return {boolean}
 */
var wordPattern = function(pattern, str) {
    const pArr = pattern.split('')
    const sArr = str.split(' ')
    const pLen = pArr.length
    const sLen = sArr.length
    if (pLen !== sLen) {
        return false
    }
    const mapP = new Map()
    const mapS = new Map()
    for (let i = 0; i < pLen; i++) {
        const pat = pArr[i]
        const s = sArr[i]
        if (!mapP.has(pat)) {
            mapP.set(pat, s)
        } else {
            if (mapP.get(pat) !== s) {
                return false
            }
        }
        if (!mapS.has(s)) {
            mapS.set(s, pat)
        } else {
            if (mapS.get(s) !== pat) {
                return false
            }
        }
    }
    return true
};