0
点赞
收藏
分享

微信扫一扫

POJ 2484 A Funny Game(简单博弈)


A Funny Game


Time Limit: 1000MS

 

Memory Limit: 65536K

Total Submissions: 4193

 

Accepted: 2558


Description


Alice and Bob decide to play a funny game. At the beginning of the game they pick n(1 <= n <= 10 6) coins in a circle, as Figure 1 shows. A move consists in removing one or two adjacent coins, leaving all other coins untouched. At least one coin must be removed. Players alternate moves with Alice starting. The player that removes the last coin wins. (The last player to move wins. If you can't move, you lose.) 




POJ   2484    A Funny Game(简单博弈)_Memory

 


Figure 1


Note: For n > 3, we use c1, c2, ..., cn to denote the coins clockwise and if Alice remove c2, then c1 and c3 are NOT adjacent! (Because there is an empty place between c1 and c3.) 



Suppose that both Alice and Bob do their best in the game. 


You are to write a program to determine who will finally win the game.


Input


There are several test cases. Each test case has only one line, which contains a positive integer n (1 <= n <= 10 6). There are no blank lines between cases. A line with a single 0 terminates the input. 


Output


For each test case, if Alice win the game,output "Alice", otherwise output "Bob". 


Sample Input


12 3 0


Sample Output


AliceAlice Bob


Source


POJ Contest,Author:Mathematica@ZSU





#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>

using namespace std;

int main()
{
    int n,m;
    while(scanf("%d",&n)!=EOF)
    {
        if(n == 0)
        {
            break;
        }
        if(n<3)
        {
            printf("Alice\n");
        }
        else
        {
            printf("Bob\n");
        }
    }
    return 0;
}


举报

相关推荐

0 条评论