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JSON 值的获取

崭新的韭菜 2022-03-24 阅读 114
JSON

方法一

		// 1.定义基本格式
        var person={"name":"zhangsan","age":23,"gender":true};
        //2.获取name的值
        var name = person.name;
        alert(name);

方法二

	 	// 1.定义基本格式
        var person={"name":"zhangsan","age":23,"gender":true};
        //获取name的值
        var name = person["name"];
        alert(name);

如果是数组的形式

	var person = {
            "person": [
                {"name": "张三", "age": 23, "gender": true},
                {"name": "李四", "age": 23, "gender": true},
                {"name": "王五", "age": 23, "gender": true}
                ]
        };

        var name1 = person.person[2].name;
        alert(name1);
	var ps=[{"name": "张三", "age": 23, "gender": true},
            {"name": "李四", "age": 23, "gender": true},
            {"name": "王五", "age": 23, "gender": true}];
            
        alert(ps[1].name);

获取所有对象中所有的键和值
		var person={"name":"zhangsan","age":23,"gender":true};
        //获取所有对象中所有的键和值
        for (var key in person) {
            alert(key+":"+person[key]);
        }


或取数组的所有值: 采用一个双重for循环的方法

var ps = [{"name": "张三", "age": 23, "gender": true},
        {"name": "李四", "age": 23, "gender": true},
        {"name": "王五", "age": 23, "gender": true}];
 for (var i = 0; i < ps.length; i++) {
        var p = ps[i];
        for (var key in p) {
            alert(key + ":" + p[key]);
        }
    }
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