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题目:
​​​题目链接:​​

题解:
贪心+排序

#include  <bits/stdc++.h>
using namespace std;
long long a[1000005];
int main()
{
int n;
cin>>n;
long long sum1=0,sum2=0;
for(int i=1;i<=n;i++)
{
scanf("%lld",&a[i]);
sum2+=a[i];
}
sort(a+1,a+1+n);
int x=n/2;
int y=n-x;
for(int i=1;i<=x;i++)
{
sum1+=a[i];
}
sum2-=2*sum1;
cout<<"Outgoing #: "<<y<<endl;
cout<<"Introverted #: "<<x<<endl;
cout<<"Diff = "<<sum2<<endl;
return 0;
}


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