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1031. Hello World for U (20)


1031. Hello World for U (20)



时间限制


400 ms






内存限制


65536 kB






代码长度限制


16000 B






判题程序


Standard



作者


CHEN, Yue





Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:
h d
e l
l r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n
1characters, then left to right along the bottom line with n
2 characters, and finally bottom-up along the vertical line with n
3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n
1 = n
3 = max { k| k <= n
2 for all 3 <= n
2 <= N } with n
1 + n
2 + n
3 - 2 = N.

Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
helloworld!
Sample Output:
h !
e d
l l
lowor
对于一个字符串,把它尽量的弄成正方形的u;题目中的n1和n3为左右数量包括最后一行的头尾,n2为最后一行的数量。所以n1+n2+n3=N-2;

代码中的left_1=n1-1=(len-1)/3这里减一是为了不数最后一行的头;wordspacing=n2-2一行空格数;
#include<string> 字符串处理 用到substr(起始位置的标号,要输出的个数);
比如 HelloWorld="12345";HelloWorld.substr(1, 3)那么输出从HelloWorld[1]开始向后输出3个为234;

N>=5
1.
12345



1 5
234
2.
123456

1 6
2345
3.
1234567

1 7
2 6
345

评测结果

时间

结果

得分

题目

语言

用时(ms)

内存(kB)

用户

8月02日

09:17

答案正确

​​20​​

​​1031​​

​​C++ (g++ 4.7.2)​​

1

308

​​datrilla​​

测试点

测试点

结果

用时(ms)

内存(kB)

得分/满分

0

答案正确

1

256

8/8

1

答案正确

1

308

2/2

2

答案正确

1

180

2/2

3

答案正确

1

308

2/2

4

答案正确

1

304

2/2

5

答案正确

1

308

2/2

6

答案正确

1

180

2/2

#include<iostream>   
#include<string>
using namespace std;
void worldspace(int size)
{
for (int index = 0; index < size; index++)
cout << " ";
}
int main()
{
string HelloWorld;
int left_1, len,index,wordspacing;
cin >> HelloWorld;
len = HelloWorld.size();
left_1 = (len -1)/ 3;
wordspacing = len - 2 * left_1 - 2;
for (index = 0; index < left_1; index++)
{
cout << HelloWorld[index];
worldspace(wordspacing);
cout << HelloWorld[len - 1 - index] << endl;;
}
cout << HelloWorld.substr(left_1, wordspacing+2) << endl;
system("pause");
return 0;
}

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