解题思路
先统计连续的0和1分别有多少个,如:111100011000,得到4323;在4323中的任意相邻两个数字,取小的一个加起来,就是3+2+2 = 7.
代码
class Solution:
def countBinarySubstrings(self, s: str) -> int:
list = []
count = 1
sum_number = 0
for i in range(1,len(s)):
if s[i] == s[i-1]:
count += 1
else:
list.append(count)
count = 1
list.append(count)
for i in range(len(list)-1):
sum_number += min(list[i],list[i+1])
return sum_number