Problem C: 让动物们叫起来吧！

Problem C: 让动物们叫起来吧！

Time Limit: 1 Sec   Memory Limit: 128 MB

Submit: 1591  

Solved: 1281

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Description

Tom家里养了很多动物，比如有鸭子、火鸡和公鸡。它们的叫声都不相同。现在，请编写类Animal、Cock、Turkey和Duck，根据给出的main()函数及样例分析每个类的属性、行为及相互关系，以模仿Tom家的情况。

提示：动物们都有自己的名字。

Input

输入有多行。第一行正整数M表示之后有M个测试用例，每个测试用例包括2部分：前一部分是动物的名字，后一部分是动物的类型（用A、B、C分别表示鸭子、火鸡和公鸡）。

Output

输出有M行，每个测试用例对应一样。见样例。

Sample Input

3Baby CRubby BTobby A

Sample Output

Baby is a cock, and it can crow.Rubby is a turkey, and it can gobble.Tobby is a duck, and it can quack.

HINT

Append Code

append.cc,

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#include <iostream>
#include <iomanip>
using namespace std;
class Animal
{
protected:
    string name;
public:
   virtual void sound()const = 0;
public:
    Animal(){ }
    Animal(string n) : name(n){  }
    virtual ~Animal(){ }
};
 
class Cock : virtual public Animal
{
public:
   void sound() const
   {
       cout << name << " is a cock, and it can crow." << endl;
   }
public:
    Cock(string n) : Animal(n){ }
    ~Cock(){ }
};
class Turkey : virtual public Animal
{
public:
   void sound() const
   {
       cout << name << " is a turkey, and it can gobble." << endl;
   }
public:
    Turkey(string n) : Animal(n){ }
    ~Turkey(){ }
};
class Duck : virtual public Animal
{
public:
   void sound() const
   {
       cout << name << " is a duck, and it can quack." << endl;
   }
public:
    Duck(string n) : Animal(n){ }
    ~Duck(){ }
};
int main()
{
    int cases;
    string name;
    char type;
    Animal *animal;
    cin>>cases;
    for (int i = 0; i < cases; i++)
    {
       cin>>name>>type;
       switch(type)
       {
        case 'A':
            animal = new Duck(name);
            break;
        case 'B':
            animal = new Turkey(name);
            break;
        case 'C':
            animal = new Cock(name);
            break;
       }
       animal->sound();
    }
    return 0;
}