0
点赞
收藏
分享

微信扫一扫

179. Largest Number

zhongjh 2022-08-03 阅读 77


Given a list of non negative integers, arrange them such that they form the largest number.

For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330.

Note: The result may be very large, so you need to return a string instead of an integer.

class NumbersComparator implements Comparator<String> {
@Override
public int compare(String s1, String s2) {
return (s2 + s1).compareTo(s1 + s2);
}
}

public class Solution {
public String largestNumber(int[] nums) {
String[] strs = new String[nums.length];
for (int i = 0; i < nums.length; i++) {
strs[i] = Integer.toString(nums[i]);
}
Arrays.sort(strs, new NumbersComparator());
StringBuilder sb = new StringBuilder();
for (int i = 0; i < strs.length; i++) {
sb.append(strs[i]);
}
String result = sb.toString();
int index = 0;
while (index < result.length() && result.charAt(index) == '0') {
index++;
}
if (index == result.length()) {
return "0";
}
return result.substring(index);
}
}

public class Solution {    
public String largestNumber(int[] nums) {
if (nums == null || nums.length == 0) {
return "0";
}
int sum = 0;
List<String> list = new ArrayList<String>();
for(int i=0; i < nums.length; i++) {
sum += nums[i];
list.add(String.valueOf(nums[i]));
}
if(sum == 0) return "0";
Collections.sort(list, (x, y) -> -(x+y).compareTo(y+x));
StringBuilder sb = new StringBuilder();
for(int i=0; i < list.size(); i++) {
sb.append(list.get(i));
}

return sb.toString();
}
}


举报

相关推荐

0 条评论