Json和字符串的处理

1、既可以去重复，又可以排序

Set<String> timeList=new TreeSet<String>();

2、这要是一种排序

Map<String,List<Map<String,String>>> result = new TreeMap<>(new Comparator<String>() {
          @Override
          public int compare(String obj1, String obj2) {
            // 降序排序
            return obj1.compareTo(obj2);
          }
        });

3、获得String中的数据，并封装成一个对象

Gson gson = new Gson();
List<String> temperature=new ArrayList<>();
EnvisionStringArray obj=gson.fromJson(map.get(metrics.get(i)),EnvisionStringArray.class);
List<String>   abc=gson.fromJson(map.get(metrics.get(i)),EnvisionStringArray.class).getValue();

获得时间，放到List集合中，然后进行排序

List<String> timeList = new ArrayList<>();
EnTime beginTempTime = new EnTime(beginTime);
EnTime endTempTime = new EnTime(endTime);
EnTime nextTime = beginTempTime.add(intervalTime*1000);
timeList.add(beginTempTime.format());
while (nextTime.le(endTempTime)){
  timeList.add(nextTime.format());
  nextTime = nextTime.add(intervalTime*1000);
}
  //实现排序方法
  Collections.sort(timeList, new Comparator() {
    @Override
    public int compare(Object o1, Object o2) {
      String str1 = (String) o1;
      String str2 = (String) o2;
      if (str1.compareToIgnoreCase(str2)<0){
        return -1;
      }
      return 1;
    }
  });