10.6

int n, m;

double i, j;

n = 2.0 * 5;

m = 5.0 / 6;

i = 56 - 23.1;

j = 99.3 + 55.2;

printf("%d %d %f %f ",n,m,i,j);

int n, m;

scanf_s("%d", &n);

scanf_s("%d", &m);

printf("%f\n", (double)(n + m) / 2.0);