题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
-- 解决方案(1)
SELECT
id,
`name`
FROM
Students AS s
WHERE NOT EXISTS(
SELECT
1
FROM
Departments
WHERE
id = s.department_id
);
-- 解决方案(2)
SELECT id, name
FROM Students
WHERE department_id NOT IN (SELECT id FROM Departments)