题目链接:
序列重组矩阵_牛客题霸_牛客网 (nowcoder.com)https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966?tpId=107&difficulty=&judgeStatus=&tags=&title=103&gioEnter=menu
解题思路:
1. 从题目上来看,输入的是一维数组,但输出结果却要求是二维数组
2. 我们可以一开始就把输入的数字放在二维数组中
3. 二维数组在打印时不要忘了换行符代码
答案代码:
#include <stdio.h>
int main ()
{
int data1 = 0,data2 = 0;
scanf("%d %d\n",&data1,&data2);
int i = 0;
int arr[10][10] = {0};
for (i = 0;i < data1;i++) //输入
{
int j = 0;
for (j = 0;j < data2;j++)
{
scanf("%d ",&arr[i][j]);
}
}
int row = 0;
for (row = 0;row < data1;row++) //输出
{
int line = 0;
for (line = 0;line < data2;line++)
{
printf("%d ",arr[row][line]);
}
printf("\n");//二维数组在打印时不要忘了换行符代码
}
return 0;
}