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字节-手串

林肯公园_97cc 2022-04-24 阅读 49
c++

参考:https://blog.csdn.net/weixin_41879093/article/details/104856812

#include <iostream>
#include <vector>

using namespace std;
int main() {
	int n, m, c;
	cin >> n >> m >> c;
	//存储每种颜色对应的珠子索引
	vector<vector<int>> num;
	for (int i = 0; i < c; i++) {//初始化
		vector<int> tmp;
		num.push_back(tmp);
	}

	//分颜色记录每个颜色出现的珠子位置
	for (int i = 0; i < n; i++) {
		int num_i;
		cin >> num_i;
		int tmp;
		for (int j = 0; j < num_i; j++) {
			cin >> tmp;
			if (tmp)
				num[tmp - 1].push_back(i);
		}
	}

	int res = 0;
	for (int i = 0; i < c; i++) {
		int len = num[i].size();

		int flag = 0;
		for (int j = 0; j < len - 1; j++) {
			if (num[i][j + 1] - num[i][j] + 1 <= m) {
				res++;
				flag = 1;
				break;
			}
		}
		//防止重复计算
		if (!flag && (num[i][0] + n - 1 - num[i][len - 1] + 2) <= m) {
			res++;
		}
	}
	cout << res << endl;
	return 0;
}
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