ZOJ Problem Set - 3878
Convert QWERTY to Dvorak
Time Limit: 2 Seconds
Memory Limit: 65536 KB
Edward, a poor copy typist, is a user of the Dvorak Layout. But now he has only a QWERTY Keyboard with a brokenCaps Lock key, so Edward never presses the brokenCaps Lock
The QWERTY Layout and the Dvorak Layout are in the following:
The QWERTY Layout |
The Dvorak Layout |
Input
A QWERTY document Edward typed. The document has no more than 100 kibibytes. And there are no invalid characters in the document.
Output
The Dvorak document.
Sample Input
Jgw Gqm Andpw a H.soav Patsfk f;doe
Nfk Gq.d slpt a X,dokt vdtnsaohe
Kjd yspps,glu pgld; aod yso kd;kgluZ
1234567890
`~!@#$%^&*()}"']_+-=ZQqWEwe{[\|
ANIHDYf.,bt/
ABCDEFuvwxyz
Sample Output
Hi, I'm Abel, a Dvorak Layout user.
But I've only a Qwerty keyboard.
The following lines are for testing:
1234567890
`~!@#$%^&*()+_-={}[]:"'<>,.?/\|
ABCDEFuvwxyz
AXJE>Ugk,qf;
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
char a[1100000];//这块很坑(WA了一下午),题中说的时100 “kibibytes”,没看清,只开到110,一直错
int main()
{
char c;
while(gets(a)!=NULL)
{
int l=strlen(a);
for(int i=0;i<l;i++)
{
if(a[i]=='Q')a[i]='\"';
else if(a[i]=='q')a[i]=39;
else if(a[i]=='W')a[i]='<';
else if(a[i]=='w')a[i]=',';
else if(a[i]=='E')a[i]='>';
else if(a[i]=='e')a[i]='.';
else if(a[i]=='R')a[i]='P';
else if(a[i]=='r')a[i]='p';
else if(a[i]=='T')a[i]='Y';
else if(a[i]=='t')a[i]='y';
else if(a[i]=='Y')a[i]='F';
else if(a[i]=='y')a[i]='f';
else if(a[i]=='U')a[i]='G';
else if(a[i]=='u')a[i]='g';
else if(a[i]=='I')a[i]='C';
else if(a[i]=='i')a[i]='c';
else if(a[i]=='O')a[i]='R';
else if(a[i]=='o')a[i]='r';
else if(a[i]=='P')a[i]='L';
else if(a[i]=='p')a[i]='l';
else if(a[i]=='{')a[i]='?';
else if(a[i]=='[')a[i]='/';
else if(a[i]=='}')a[i]='+';
else if(a[i]==']')a[i]='=';
else if(a[i]=='A')a[i]='A';
else if(a[i]=='a')a[i]='a';
else if(a[i]=='S')a[i]='O';
else if(a[i]=='s')a[i]='o';
else if(a[i]=='D')a[i]='E';
else if(a[i]=='d')a[i]='e';
else if(a[i]=='F')a[i]='U';
else if(a[i]=='f')a[i]='u';
else if(a[i]=='G')a[i]='I';
else if(a[i]=='g')a[i]='i';
else if(a[i]=='H')a[i]='D';
else if(a[i]=='h')a[i]='d';
else if(a[i]=='J')a[i]='H';
else if(a[i]=='j')a[i]='h';
else if(a[i]=='K')a[i]='T';
else if(a[i]=='k')a[i]='t';
else if(a[i]=='L')a[i]='N';
else if(a[i]=='l')a[i]='n';
else if(a[i]==':')a[i]='S';
else if(a[i]==';')a[i]='s';
else if(a[i]=='\"')a[i]='_';
else if(a[i]==39)a[i]='-';
else if(a[i]=='Z')a[i]=':';
else if(a[i]=='z')a[i]=';';
else if(a[i]=='X')a[i]='Q';
else if(a[i]=='x')a[i]='q';
else if(a[i]=='C')a[i]='J';
else if(a[i]=='c')a[i]='j';
else if(a[i]=='V')a[i]='K';
else if(a[i]=='v')a[i]='k';
else if(a[i]=='B')a[i]='X';
else if(a[i]=='b')a[i]='x';
else if(a[i]=='N')a[i]='B';
else if(a[i]=='n')a[i]='b';
else if(a[i]=='M')a[i]='M';
else if(a[i]=='m')a[i]='m';
else if(a[i]=='<')a[i]='W';
else if(a[i]==',')a[i]='w';
else if(a[i]=='>')a[i]='V';
else if(a[i]=='.')a[i]='v';
else if(a[i]=='?')a[i]='Z';
else if(a[i]=='/')a[i]='z';
else if(a[i]=='_')a[i]='{';
else if(a[i]=='-')a[i]='[';
else if(a[i]=='+')a[i]='}';
else if(a[i]=='=')a[i]=']';
}
for(int i=0;i<l;i++)
printf("%c",a[i]);
printf("\n");
}
return 0;
}
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
char a[]={"QqWwEeRrTtYyUuIiOoPp{[}]AaSsDdFfGgHhJjKkLl:;\"'ZzXxCcVvBbNnMm<,>.?/_-+="};
char b[]={"\"'<,>.PpYyFfGgCcRrLl?/+=AaOoEeUuIiDdHhTtNnSs_-:;QqJjKkXxBbMmWwVvZz{[}]"};
char c;
char print(char c)
{
for(int i=0;a[i];i++)
if(a[i]==c)
return b[i];
return c;
}
int main()
{
while(scanf("%c",&c)!=EOF)
printf("%c",print(c));
return 0;
}