PTA L1-018：大笨钟 (python)

一、题目要求

二、参考代码

time =input()
t = [int(i) for i in time.split(':')]
if 0<=t[0]<=23 and 0<=t[1]<=59:
    sub = t[0]-12
    if sub<0:
        print('Only '+time+'.  Too early to Dang.')
    elif sub==0:
        if t[1]==0:
            print('Only '+time+'.  Too early to Dang.')
        else:
            print('Dang')
    else:
        if t[1]!=0:
            print('Dang'*(sub+1))
        else:
            print('Dang'*sub)