Forgotten Spell Gym - 101755M

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恶心思维模拟 记出现三种,两种,一种字符的位置的数量分别为v3 v2 v1

(1) v3>1 不可能 因为每人最多错一次

(2) v3==1

    (1) v2>1 不可能

    (2) v2==1 这时情况很复杂 很难继续分类讨论 直接暴力枚举出现三种和两种字符的那两个位置 然后看有几种结果

    (3) 模棱两可 可能有一人是对的 有可能全错

(3) v3==0 情况更复杂... 见代码

#include <bits/stdc++.h>
using namespace std;

int pre[4][200010];
int n;
char a[200010],b[200010],c[200010],ans[200010];

int solve(char aa,char bb,char cc)
{
    int book[30];
    int i,res;
    memset(book,0,sizeof(book));
    book[aa-'a']++,book[bb-'a']++,book[cc-'a']++;
    res=0;
    for(i=0;i<26;i++)
    {
        if(book[i]!=0) res++;
    }
    return res;
}

int gou(int p1,int p2,char aa,char bb)
{
    int book[4][3];
    int i;
    memset(book,0,sizeof(book));
    if(a[p1]==aa) book[1][1]=1;
    if(a[p2]==bb) book[1][2]=1;
    if(b[p1]==aa) book[2][1]=1;
    if(b[p2]==bb) book[2][2]=1;
    if(c[p1]==aa) book[3][1]=1;
    if(c[p2]==bb) book[3][2]=1;
    for(i=1;i<=3;i++)
    {
        if(!book[i][1]&&!book[i][2]) return 0;
    }
    return 1;
}

int gougou(int p1,int p2,int p3,char aa,char bb,char cc)
{
    int book[4][4];
    int i,j,cnt;
    memset(book,0,sizeof(book));
    if(a[p1]==aa) book[1][1]=1;
    if(a[p2]==bb) book[1][2]=1;
    if(a[p3]==cc) book[1][3]=1;
    if(b[p1]==aa) book[2][1]=1;
    if(b[p2]==bb) book[2][2]=1;
    if(b[p3]==cc) book[2][3]=1;
    if(c[p1]==aa) book[3][1]=1;
    if(c[p2]==bb) book[3][2]=1;
    if(c[p3]==cc) book[3][3]=1;
    for(i=1;i<=3;i++)
    {
        cnt=0;
        for(j=1;j<=3;j++)
        {
            if(!book[i][j]) cnt++;
        }
        if(cnt>1) return 0;
    }
    return 1;
}

int main()
{
    int book[4];
    int i,res,p;
    int cnt,p1,p2,p3;
    char tem,ii,jj,kk;
    while(scanf("%s%s%s",a,b,c)!=EOF)
    {
        memset(book,0,sizeof(book));
        n=strlen(a);
        for(i=0;i<n;i++)
        {
            res=solve(a[i],b[i],c[i]);
            book[res]++;
            pre[res][book[res]]=i;
        }
        if(book[3]>1)
        {
            printf("Impossible\n");
        }
        else if(book[3]==1)
        {
            if(book[2]==0)
            {
                printf("Ambiguous\n");
            }
            else if(book[2]==1)
            {
                cnt=0,p1=pre[3][1],p2=pre[2][1];
                memcpy(ans,a,sizeof(a));
                for(ii='a';ii<='z';ii++)
                {
                    for(jj='a';jj<='z';jj++)
                    {
                        if(gou(p1,p2,ii,jj))
                        {
                            cnt++;
                            ans[p1]=ii,ans[p2]=jj;
                        }
                    }
                }
                if(cnt==0)
                {
                    printf("Impossible");
                }
                else if(cnt>1)
                {
                    printf("Ambiguous\n");
                }
                else
                {
                    printf("%s\n",ans);
                }
            }
            else
            {
                printf("Impossible\n");
            }
        }
        else
        {
            if(book[2]==0)
            {
                printf("Ambiguous\n");
            }
            else if(book[2]==1)
            {
                printf("Ambiguous\n");
            }
            else if(book[2]==2)
            {
                cnt=0,p1=pre[2][1],p2=pre[2][2];
                memcpy(ans,a,sizeof(a));
                for(ii='a';ii<='z';ii++)
                {
                    for(jj='a';jj<='z';jj++)
                    {
                        if(gou(p1,p2,ii,jj))
                        {
                            cnt++;
                            ans[p1]=ii,ans[p2]=jj;
                        }
                    }
                }
                if(cnt==0)
                {
                    printf("Impossible");
                }
                else if(cnt>1)
                {
                    printf("Ambiguous\n");
                }
                else
                {
                    printf("%s\n",ans);
                }
            }
            else if(book[2]==3)
            {
                cnt=0,p1=pre[2][1],p2=pre[2][2],p3=pre[2][3];
                memcpy(ans,a,sizeof(a));
                for(ii='a';ii<='z';ii++)
                {
                    for(jj='a';jj<='z';jj++)
                    {
                        for(kk='a';kk<='z';kk++)
                        {
                            if(gougou(p1,p2,p3,ii,jj,kk))
                            {
                                cnt++;
                                ans[p1]=ii,ans[p2]=jj,ans[p3]=kk;
                            }
                        }
                    }
                }
                if(cnt==0)
                {
                    printf("Impossible");
                }
                else if(cnt>1)
                {
                    printf("Ambiguous\n");
                }
                else
                {
                    printf("%s\n",ans);
                }
            }
            else
            {
                printf("Impossible\n");
            }
        }
    }
    return 0;
}