oracle 统计某个字符出现的次数

1.情景展示

在oracle当中，如何统计某个字符/指定字符串在字符串中出现的次数？

如：411600,411602,411603,411606,411609,411621,411622,411623,411624,411625,411626,411627,411628,411643,411681。

2.具体分析

通过LENGTHB()+TRANSLATE()或者LENGTHB()+REPLACE()实现。

3.解决方案

方式一：LENGTHB(TRANSLATE(string, character || string, character))

SELECT LENGTHB(TRANSLATE('411600,411602,411603,411606,411609,411621,411622,411623,411624,411625,411626,411627,411628,411643,411681',
                         ',' ||
                         '411600,411602,411603,411606,411609,411621,411622,411623,411624,411625,411626,411627,411628,411643,411681',
                         ','))
  FROM DUAL

TRANSLATE(string, character || string, character)：只保留某些特定字符，并将其余字符排除。

方式二：LENGTHB(string)-LENGTHB(REPLACE(string, character, ''))

SELECT LENGTHB('411600,411602,411603,411606,411609,411621,411622,411623,411624,411625,411626,411627,411628,411643,411681') -
       LENGTHB(REPLACE('411600,411602,411603,411606,411609,411621,411622,411623,411624,411625,411626,411627,411628,411643,411681,',
                       ',',
                       ''))
  FROM DUAL;

REPLACE(string, character, '')：将字符串当中的特定字符替换成空。

写在最后

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