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蓝桥杯单片机第十三届模拟题

AbrahamW 2022-03-18 阅读 61

全部文件:提取码:azxy
这个模拟题主要容易出错的地方是通道1和3的切换时只会读取通道1的值,只要把IIC_SendAck(0)改成IIC_SendAck(1)就可以了。
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在这里插入图片描述
在这里插入图片描述

#include "STC15F2K60S2.h"
#include "iic.h"
typedef unsigned char u8;
typedef unsigned int u16;
sbit S4=P3^3;
sbit S5=P3^2;
sbit S6=P3^1;
sbit S7=P3^0;

//					0	 1	  2	   3    4    5    6    7    8    9  
u8 code duan[12]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0xff,0xbf};
u8 model=1;//界面标志
u16 pl=0,pl_hc=0;//频率和频率缓存
u16 tt=0;//周期
u16 uu=0,uu_hc=0;//通道电压和通道3电压缓存
u8 td=1;//通道
u16 count=0;//定时器0脉冲
u8 count1=0;//1S标志
u16 count2=0;//长按判断
u8 led_close=0;//LED关闭标志

void delay(u16 i)
{
	while(i--);
}

void Delay5ms()	
{
	unsigned char i, j;

	i = 59;
	j = 90;
	do
	{
		while (--j);
	} while (--i);
}

void TimerInit(void)		
{
	AUXR |= 0x40;		
	TMOD = 0x16;		
	TL1 = 0xA0;		//5ms 
	TH1 = 0x15;		
	TL0 = 0xff;
	TH0 = 0xff;
	TR1 = 1;	
	TR0 = 1;	
	ET0 = 1;
	ET1 = 1;
	EA = 1;
}

void Service_T0() interrupt 1
{
	count++;
}

void Service_T1() interrupt 3
{
	count1++;
	if(count1==200)
	{
		pl=count;
		count=0;
		count1=0;
	}
}

void Chan_hc573(chose)
{
	switch(chose)
	{
		case 4:
			P2 = (P2 & 0x1f) | 0x80; break;
		case 5:
			P2 = (P2 & 0x1f) | 0xa0; break;
		case 6:
			P2 = (P2 & 0x1f) | 0xc0; break;
		case 7:
			P2 = (P2 & 0x1f) | 0xe0; break;
	}
}

void Init_system()
{
	Chan_hc573(5);
	P0=0x00;
	Chan_hc573(4);
	P0=0xff;
}

void Smg_display(u8 com,u8 dat)
{
	Chan_hc573(7);
	P0=0xff;
	Chan_hc573(6);
	P0=0x01<<com;
	Chan_hc573(7);
	P0=dat;
}

void Close_smg()
{
	Chan_hc573(6);
	P0=0x00;
	Chan_hc573(7);
	P0=0xff;
}

void Display_f_n_u()
{
	if(model==1)
	{
		Smg_display(0,0x8e); delay(1000);
		Smg_display(1,duan[10]); delay(1000);
		Smg_display(2,duan[10]); delay(1000);
		if(pl>9999) {Smg_display(3,duan[pl/10000]); delay(1000);}
		if(pl>999) {Smg_display(4,duan[(pl/1000)%10]); delay(1000);}
		if(pl>99) {Smg_display(5,duan[(pl/100)%10]); delay(1000);}
		if(pl>9) {Smg_display(6,duan[(pl/10)%10]); delay(1000);}
		Smg_display(7,duan[pl%10]); delay(1000);
		Close_smg();
	}
	else if(model==2)
	{
		tt=1000000/pl;
		Smg_display(0,0xc8); delay(1000);
		Smg_display(1,duan[10]); delay(1000);
		Smg_display(2,duan[10]); delay(1000);
		if(tt>9999) {Smg_display(3,duan[tt/10000]); delay(1000);}
		if(tt>999) {Smg_display(4,duan[(tt/1000)%10]); delay(1000);}
		if(tt>99) {Smg_display(5,duan[(tt/100)%10]); delay(1000);}
		if(tt>9) {Smg_display(6,duan[(tt/10)%10]); delay(1000);}
		Smg_display(7,duan[tt%10]); delay(1000);
		Close_smg();
	}
	else if(model==3)
	{
		Smg_display(0,0xc1); delay(1000);
		Smg_display(1,duan[11]); delay(1000);
		Smg_display(2,duan[td]); delay(1000);
		Smg_display(3,duan[10]); delay(1000);
		Smg_display(4,duan[10]); delay(1000);
		Smg_display(5,duan[(uu/100)%10]+0x80); delay(1000);
		Smg_display(6,duan[(uu/10)%10]); delay(1000);
		Smg_display(7,duan[uu%10]); delay(1000);
		Close_smg();
	}
}

void Key_down()
{
	if(S4==0)
	{
		delay(100);
		if(S4==0)
		{
			while(S4==0) {Display_f_n_u();}
			model++;
			if(model==4) {model=1;}
		}
	}
	if(S5==0)
	{
		delay(100);
		if(S5==0)
		{
			while(S5==0) {Display_f_n_u();}
			if(model==3)
			{
				if(td==1) {td=3;}
				else if(td==3) {td=1;}
			}
		}
	}
	if(S6==0)
	{
		delay(100);
		if(S6==0)
		{
			while(S6==0) {Display_f_n_u();}
			if(td==3) {uu_hc=uu;}
		}
	}
	if(S7==0)
	{
		delay(100);
		if(S7==0)
		{
			while(S7==0) {Display_f_n_u();count2++;Delay5ms();}
			if(count2<=200) {count2=0;pl_hc=pl;}
			else if(count2>200) {count2=0;led_close=~led_close;}
		}
	}
}

void Read_td()
{
	if(td==1) {uu=read_pcf8591(1)/0.51;}
	else if(td==3) {uu=read_pcf8591(3)/0.51;}
}

void Led()
{
	Chan_hc573(4);
	if(led_close==0)
	{
		if(uu>uu_hc) {P00=0;}
		if(pl>pl_hc) {P01=0;}
		if(model==1) {P02=0;}
		else if(model==2) {P03=0;}
		else if(model==3) {P04=0;}
	}
	else P0=0xff;
}

void main()
{
	Init_system();
	TimerInit() ;
	while(1)
	{
		Led();
		Read_td();
		Key_down();
		Display_f_n_u();
	}
}
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