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Python学习:批量启动多线程


建立一个线程池,并将某个线程放入进去

threadpool = []
th = threading.Thread(target=func_name, args=func_args)
threadpool.append(th)

批量加入线程

for i in range(10):
th = threading.Thread(target=func_name, args=func_args)
threadpool.append(th)

批量开始线程

for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)

实例如下:

import time
import threading


def matter1(music, test):
print test, music
# 假设每一首歌曲的时间是2秒
time.sleep(2)


if __name__ == '__main__':
# 设定我要听的歌为
musics = ["music1", "music2", "music3"]
test = "122678"
# 开始时间
start = time.time()

threadpool = []

for music in musics:
th = threading.Thread(target=matter1, args=(music, test))
threadpool.append(th)
for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)

# 结束时间
end = time.time()
print("完成的时间为:" + str(end - start))

完成同时听三首歌线程,花费时间 2s:

Python学习:批量启动多线程_开发语言


限制线程数量可以使用Semaphore,实例如下:

import time
import threading

#Python学习交流群:711312441
#添加一个计数器
s1=threading.Semaphore(2)

def matter1(music, test):
# 计数器获得锁
s1.acquire()
print(test, music)
# 假设每一首歌曲的时间是2秒
time.sleep(2)
# 计数器释放锁
s1.release()


if __name__ == '__main__':
# 设定我要听的歌为
musics = ["music1", "music2", "music3"]
test = "122678"
# 开始时间
start = time.time()

threadpool = []

for music in musics:
th = threading.Thread(target=matter1, args=(music, test))
threadpool.append(th)
for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)

# 结束时间
end = time.time()
print("完成的时间为:" + str(end - start))

完成听前2首歌线程,花费时间 2s:

Python学习:批量启动多线程_学习_02


听第3首歌花费 2s,最后一共花费 4s:

Python学习:批量启动多线程_python_03


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