Python 3 内置函数 - zip()函数

0. zip()函数

1. 使用方法

>>> help(zip)

# output:
Help on class zip in module builtins:

class zip(object)
 |  zip(*iterables) --> A zip object yielding tuples until an input is exhausted.
 |  
 |     ## 使用方法
 |     >>> list(zip('abcdefg', range(3), range(4)))
 |     [('a', 0, 0), ('b', 1, 1), ('c', 2, 2)]
 |  
 |  The zip object yields n-length tuples, where n is the number of iterables
 |  passed as positional arguments to zip().  The i-th element in every tuple
 |  comes from the i-th iterable argument to zip().  This continues until the
 |  shortest argument is exhausted.
 |  
 |  Methods defined here:
 |  
 |  __getattribute__(self, name, /)
 |      Return getattr(self, name).
 |  
 |  __iter__(self, /)
 |      Implement iter(self).
 |  
 |  __next__(self, /)
 |      Implement next(self).
 |  
 |  __reduce__(...)
 |      Return state information for pickling.
 |  
 |  ----------------------------------------------------------------------
 |  Static methods defined here:
 |  
 |  __new__(*args, **kwargs) from builtins.type
 |      Create and return a new object.  See help(type) for accurate signature.

2. 使用示例

2.1. zip() 压缩

>>> a = ['a','b','c']
>>> b = [1, 2, 3]
>>> x = zip(a, b)
>>> x, list(x)

# output:
(<zip at 0x7f58142bcd00>, [('a', 1), ('b', 2), ('c', 3)])

2.1. zip(*) 解压

>>> x = [('a', 1), ('b', 2), ('c', 3)]
>>> a, b = zip(*x)
>>> a, b

# output:
(('a', 'b', 'c'), (1, 2, 3))